杭电acm解题报告 详细解析2000-2099 适合acm初学者
杭电acm解题报告 详细解析2000-2099 适合acm初学者
杭电oj4405,一道简单的概率dp题目
ACM_HDU 我的 acm 问题的一部分在 hdoj 中解决了。
原题:http://acm.hdu.edu.cn/showproblem.php?pid=10011 #include 23 int main(void)4 {5 inti,n,sum;6 sum = 0;7 while(scanf("%d",&n)!=EOF)8 {9 sum=0;10 for (i=0;i<=n;i++)11...
我去年暑假花了5天,把杭电ACM网站上2000到2099这100道题全AC了,又花了10来天精心写解题报告。 里面包括题目、解题思路、编程技巧以及参考源码。所有代码都是使用C/C++写的。 最近整理资料时无意间发现,打包...
第二版#include&lt;stdio.h&gt; int main() { int a,n,m,sum; scanf("%d",&amp;n); while(n--) { scanf("%d",&amp;m); sum=0; while(m--) ......
Billboard Time Limit: 20000/8000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 14144 Accepted Submission(s): 6058 Problem Description ...At the entrance to
Problem Description ...Nowadays, we all know that Computer College is the biggest department in HDU. But, maybe you don't know that Computer College had ever been split into Computer College and...
第一版程序#include&lt;stdio.h&gt; int main() { int a,n,sum; while(scanf("%d",&amp;n)!=EOF) { sum=0; while(n--) { scanf("%d",&amp;a);......
收集的部分HDOJ杭电ACM题的代码 大牛勿下 全是基础供初级acmer使用
Input Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the
Just a Numble Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2952 Accepted Submission(s): 1454 Problem Description ...Now give you t
里面附了自己当时做完这个题目后的心得笔记
如果有啥不正确或不合适的地方 希望能在评论里面指出
Problem Description Your task is to calculate the sum of some integers. Input Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M...
#include "stdio.h" int main(){ int i,a,b; scanf("%d",&i); while(i){ scanf("%d%d",&a,&b); printf("%d\n",a+b); i--; } return 0; }
Problem Description Your task is to calculate the sum of some integers. Input Input contains multiple test cases, and one case one line. Each case starts with an integer N, and then N...
ExponentiationTime Limit: 1000/500 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1696Accepted Submission(s): 376Problem DescriptionProblems involving the compu...
http://acm.hdu.edu.cn/showproblem.php?pid=1050 题意为: 为了叙述方便,把一个房间里面的桌子移动到另一个房间称为一个移动,给出若干个要求完成的移动,任意两个移动仅在移动路线不相交的情况下可以同时...
我的解决方案代码适用于流行的在线裁判系统,例如 POJ、HDOJ、SGU 和 ACM-ICPC Live Archive。 但是,我忘记了我用来解决这些问题的算法! 我将通过竞赛来组织代码和解决方案。 一些索引页面将可用,以便您可以更快...
http://acm.hdu.edu.cn/ 杭电 2051到2099 acm的AC解题报告
hdoj1001 hdoj1002 hdoj1003 hdoj1004 hdoj1005 hdoj1006hdoj1007 hdoj1008 hdoj1009 hdoj1010 hdoj1011 hdoj1012 hdoj1013hdoj1014 hdoj1015 hdoj1016 hdoj1017 hdoj1018 hdoj1019 hdoj1020hdoj1021 hdoj1022 hdoj1...
这份压缩包内包含了2019年杭电多校第一场的数据与标程,欢迎下载
原始方法(会超时): #include #include using namespace std; int main() { int a,b; while(scanf("%d %d",&a,&b)!=EOF) { int i,yu=(a*a)%10; for(i=2;i<=b-1;i++) { yu=(yu*a)%1
http://acm.hdu.edu.cn/showproblem.php?pid=1004 以下代码有bug!bug在哪里呢?在哪里呢?在哪里呢? #include&amp;lt;stdio.h&amp;gt; #include&amp;lt;stdlib.h&amp;gt; #include&amp;lt;...
标签: 水题
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2000 //C++代码 #include using namespace std; int main(){ char a[3]; while(cin>>a){ char ch; if(a[0]>a[1]){ ch=a[0]; a[0]=a[1]; a[1]=ch;}...
Problem Description Your task is to calculate the sum of some integers. Input Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M...
Problem Description Your task is to Calculate a + b. ...The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line. ...